Question

Calculate the no of e present in 7g of Si ⁴+​

Answer 1

Explanation:

first the number of moles

so,

float moles= 7.0/28.0855;

printf("Number of atoms = %dNa",moles)

here Na is Avagadro's Number ,i.e,6.022x10^23.

U can also get to this in this manner :-

1 mole of Si contains 6.022x10^23 atoms

also 1 mole of Si equals 28.0855 g of Si

So ,28.0855 g of Si contains 6.022x10^23 atoms

Hence,7 g of Si contains (6.022x10^23/28.0855)*7 atoms