Question

Calculate the no. Of elections present in 1.6g of methane

Answer 1

Answer:

Explanation:

1.6 g of methane, therefore is roughly 0.1 mole. A mole of any substance contains 6.023 X 10^23 molecules.

total number of electrons = number of electrons present in CH4 × atoms present in 0.1 mole.

=10×6.02 × 10^22 =6.02 × 10^23