Calculate the no. of electron constuting one colomb of charge?
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Given that
Charge (Q) = 1 C
Electron (e) = 1.6× 10^-19
Number of electron (n) = ?
Q= ne
1 C = n × 1.6×10^-19 C
n = 1/(1.6×10^-19)
n = 6.25 × 10^18 electron
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