Question

calculate the no of electron present in 2 litre of chlorine at 300k and 2.46atm press. ​

Answer 1

Explanation:

use the ideal gas eqn, Pv = nRT aubstitute all values from the question ,

2.46*2 = n*0.082*300

n = 0.2

These are the moles of Cl2 gas , now one molecules of this gas contains 34 electrons so no. of electrons will be 0.2*34*(6*10^23)