Question

calculate the no.of electrons constutingg one columb of charge

Answer 1

Q = ne
Where,
Q is charge, n is no.of electrons and e is charge on 1 electron and that is approx. 1.6 x 10^19 in negatively.
n = Q/e
n = 1C/1.6 x 10^19
n = 6.25 x 10^18 electrons

Answer 2

Given that

Charge (Q) = 1 C

Electron (e) = 1.6× 10^-19

Number of electron (n) = ?

Q= ne

1 C = n × 1.6×10^-19 C

n = 1/(1.6×10^-19)

n = 6.25 × 10^18 electron