Question

Calculate the no. of electrons emitted in 3 sec if there is 4A of current flowing in a circuit.​

Answer 1

Answer:

Given that,

Current i=5A

Time t=1s

Charge e=1.6×10

−19

C

We know that,

Q=it

ne=it

n=

e

it

n=

1.6×10

−19

5×1

n=3.125×10

19

n=3125×10

16

Hence, the number of electrons is 3125×10

16

Answer 2

Answer:

The number of electrons flowing in 3sec through the circuit in which there is a current of 4A is $n=8*10^{19}$

Explanation:

• The electric current is due to the flow of electron

• If (n) number of electrons are flowing in time (t), the current is given by the formula

       $I=\frac{ne}{t}$

where the electric charge $e=1.6*10^{-19}C$

From the question, we have

the current in the circuit is $I=4A$

the flowing time of electrons $t=3sec$

now the number of electrons $n=\frac{It}{e}$

⇒ $n=\frac{4*3}{1.6*10^{-19} } =7.5*10^{19}$

the value can be approximated as $n=8*10^{19}$