Question

calculate the no. of electrons flowing in a wire if 5 A of current flows in a wire in 8 minutes

Answer 1

Answer:

we know

Q ( charge) = no. of electron × e(charge on electron )

Explanation:

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Answer 2

solution:

the total charge flow through wire in 8 min or 480sec

I=q/t or q=It

I=5A & t= 480 sec

q= 5×480= 2400 C

q=ne where n is the of charged particles

e= charge in one electron = 1.6×10^-19 C

2400= n×1.6×10^-19

n=2400/1.6×10^-19=1.5×10^16 electrons