Calculate the no. Of electrons in1.8 gm of glucose
Answers
Answered by
3
Hey, here is ur answer
First calculate the mole if solutes
solute=glucose
No. of moles= Weight of Solute in gm/ Molecular weight
1.8/180 =.01 moles
No.of molecules= 6.22*10^23*.01= 6.22*10^21
No.of electrons in 1 molecules of glucose=96
Then after, multiply 96* 6.22*10^21
hope u got it
First calculate the mole if solutes
solute=glucose
No. of moles= Weight of Solute in gm/ Molecular weight
1.8/180 =.01 moles
No.of molecules= 6.22*10^23*.01= 6.22*10^21
No.of electrons in 1 molecules of glucose=96
Then after, multiply 96* 6.22*10^21
hope u got it
Answered by
1
1 mole of glucose(C₆H₁₂O₆=180grams) contains
(6 x 6) + (12 x 1) + (6 x 8) = (96 x Avogadro number) of e⁻
1.8 grams means 0.01 moles of glucose.
That is,
1 mole of glucose has 96 x Avogadro number of electrons
0.01 moles of glucose has "0.01 x 96 x Avogadro number of electrons"
= 0.96 x 6 x 10²³ electrons
= 5.76 x 10²³ electrons are present in 1.8 grams of glucose.
(6 x 6) + (12 x 1) + (6 x 8) = (96 x Avogadro number) of e⁻
1.8 grams means 0.01 moles of glucose.
That is,
1 mole of glucose has 96 x Avogadro number of electrons
0.01 moles of glucose has "0.01 x 96 x Avogadro number of electrons"
= 0.96 x 6 x 10²³ electrons
= 5.76 x 10²³ electrons are present in 1.8 grams of glucose.
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