Calculate the no of electrons present in 1.6 grms of mg
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24 grms of My contain = 6.022* 10²³ atoms
1 grm will contain =1/24 *6.022*10²³
1.6 grs contain ( 1.6 *6.022*10²³)/24
= 0.4015*10²³ atoms
now 1 atom of my contain 12 electrons
so no. of electrons in 0.4015 *10²³ atoms of Mg. = 0.4015 *10²³ *12 =4.818 *10²³
1 grm will contain =1/24 *6.022*10²³
1.6 grs contain ( 1.6 *6.022*10²³)/24
= 0.4015*10²³ atoms
now 1 atom of my contain 12 electrons
so no. of electrons in 0.4015 *10²³ atoms of Mg. = 0.4015 *10²³ *12 =4.818 *10²³
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