calculate the no of electrons present in 1.6gm cH⁴
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no of electrons present in 1.6 grm of CH4 =10×0.1×6.022×10^23
=6.022×10^23
=6.022×10^23
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Number of moles in 1.6gm of CH4= Given Mass/Molar Mass
=1.6/10=0.16
Now, no of electrons= No of moles × Avocado No
= 0.16 × 6.022×10²³
=0.96×10²³ (ans)
=1.6/10=0.16
Now, no of electrons= No of moles × Avocado No
= 0.16 × 6.022×10²³
=0.96×10²³ (ans)
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