Calculate the no.Of electrons present in 100g of water
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H- 2*1 electrons
O- 8 electrons
so 1 atom of H2O= 8+2 = 10 electrons
18 g of water has 6.023*10^23 atoms
so....100 g of water has = 602.3*10^23 atoms
1 atom= 10 electrons
so.... 602.3*10^23 atoms= 6023*10^23 electrons
hope it helps..
plz mark brainliest
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mole of water is equal to 18 g of H2O which is 6.023*10^23 molecules of water and also in each molecule of water there are 10 electrons(8 electrons from oxygen atom and 1 electron from each of the two hydrogen atoms).
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