Question

calculate the no. of electrons present in 19g of phosphate ion​

Answer 1

Answer:

1. 6 NA. B.

2. 7 NA. C.

3. 5 NA. D.

4. 1 NA. Medium. Answer. Mass of

PO43-=9.5 g. Number of

moles=Molecular weightWeight of

PO43-=959.5=0. 1mole=6.

023x1023ions. 0.1moles=0.1x6.

023x1023=6.023x1022ions. Each ion of

PO43- has 50 electrons. . Total number of electrons. =6. 023x1022x50. =3x1024 electrons. =6. 023x1022x2100. =6.

023x1023x210.