Question

calculate the no of electrons present in 9.5 grams of PO4^-3​

Answer 1

Answer:

The answer goes like this

Explanation:

I hope you mean (PO4)3-

Molar Mass of (PO4)3- is 95g

Given mass is 9.5g

Number of moles = 9.5/95 = 0.1

1 mole contains 6 * 10^23 components

(In this case, ions)

0.1 moles contain 6 * 10^22 ions

But each ion has 50 electrons (15+32+3)

Thus total electrons in 9.5 g of (PO4)3- is (6*10^22)*50

= 3*10^24 electrons.