Question

calculate the no. of electrons present in 9.5g of PO4^3-.

Answer 1

Moles of PO43− = Mass in g/molar mass of PO43−                              

= 9.5/31 + 4 × 16                            

= 9.5/95                   

= 0.1 mole

Number of molecules = mole × avogadro number                 
= 0.1 × 6.022 × 10^23                  

= 6.022 × 10^22

1 molecule of PO43− contains 15 + 4 × 8 + 3 = 50 electron

So,

6.022 × 10^22 contains 

= 50 × 6.022 × 10^22        

= 301.1 × 10^22 electrons

Answer 2

Explanation:

5NA electron because it has total 50 electron