Question

calculate the no. of electrons that would flow per second through the cross section of wire when 1A current flows in it.​

Answer 1

$6.25 \times {10}^{18} electrons$

Explanation:

$i = q \div t$

$given \: i = 1 \: ampere \: and \: t = 1sec$

$= > \: q = 1 \: coulumb$

$q = ne$

$1 = n \times 1.6 \times {10}^{ - 19}$

$= > n = 1 \div 1.6 \times {10}^{ - 19} = 6.25 \times {10}^{18} electrons$

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