Social Sciences, asked by bvasantharao1949, 1 year ago

calculate the no of g atoms present in 51 grms of NH3

Answers

Answered by chitrabotany

2

Answer:

NH3=17g

1 mole of NH3=17g

51g=51/17

51g=3 moles

No of atoms in 51g of NH3 is 3*4*6.022x10^23 atoms

=72.264x10^23atoms

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