calculate the no of H atom in 0.585mol C4H2
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Answer:
2×0.585×Na atom
Explanation:
0.585 mol of C4H2
1 mol contain 6.022×10²³ particle
0.585 mol contain =0.585×6.022×10²³
each C4H2 contain 2 H atom
=2×0.585×6.022×10²³atoms
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