Question

calculate the no of h atoms present in 18g of h2o

Answer 1

according to the formula , no. of atom present in 18 g of H2O = 18/18×6.023 × 10^23

Answer 2

we know that 18 gm of water contains exactly 1 mole of molecules that's equals to 6.022×10^23 molecules .
now one molecule of H^2O contains 2 hydrogen atoms so multiplying 6.022×10^23 by we get 12.044×10^23 hydrogen atoms
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