Question

Calculate the no. Of helium atoms present in 52 u

Answer 1

Explanation:

1 mol of He = 4 g = 6.022×1023atoms

∴ 52 g of He = (6.022×1023/4) × 52 atoms = 7.8286×1024atom

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Answer 2

Answer:

 1 atom of He = 4 u of He

4 u of He = 1 Atom of He

∴ 52 u of He = 1/4 × 52 = 13 atoms