Question

Calculate the no. of Hydrogen ions present in 500 mL of 0.001 M H2SO4 solution ?
6.02 X1020
3.01 x 1020
3.01 X1017
6.02 x 1017​

Answer 1

Answer:

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CBSE Class 11-science - Ask The Expert

Answered

Calculate the no.of sulphate ions in 100ml of 0.001M H2SO4 soln.

Asked by pb_ckt | 29th May, 2019, 11:36: PM

Expert Answer:

Given:

Molarity = 0.001 M

Volume of solution = 100 ml

= 0.1 L

We know,

Molarity space equals space fraction numerator No. space of space moles over denominator Volume space of space solution space in space straight L end fraction

No. space of space moles space of space straight H subscript 2 SO subscript 4 space equals space Molarity space cross times space Volume space of space solution space in space straight L

space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space equals space 0.001 space cross times space 0.1

No. space of space moles space of space straight H subscript 2 SO subscript 4 space equals space 0.0001 space mole

1 mole of H2SO4 caontains 1 mole of SO42− ions

So, there are 0.0001 moles of SO42− ions

1 mole contins Avogadro's no. of ions.

No. of ions = No. of moles × Avogadro's number

= 0.0001 × 6.022 × 1023

= 6.022 × 1019 SO42− ions