Question

Calculate the no. Of iron atom in a pieces of iron weighting 2.8 gram?

Answer 1

No. Of iron atoms will be 3.011 *10^22

Answer 2

Answer:

1 mole of iron = gram atomic mass of iron

= 56 g

We know that one mole of iron element contains 6.022 × 10²³ atoms of iron.

Now,

56 g of iron contains = 6.022 × 10²³ atoms.

So,

2.8 g of iron contains :

= 6.022 × 10²³/56 × 2.8

= 6.022 × 10²²/2

= 3.011 × 10²² atoms

Thus, a piece of iron metal having a mass of 2.8 grams contains 3.011 × 10²² atoms of iron.