Question

calculate the no of mole present in 3.011×1023 mass of nitrogen​

Answer 1

Answer:

14/2 = 7g of N

Explanation:

3.011×10 ^23 no. of nitrogen atom at mass of nitrogen =14g

1 mole of nitrogen contains 6.022×10 ^23

atoms

14g will contains 6.022×10 ^23

atoms

how,

14

____________

6.022×10 ^23 g contains 1 atom