Question

calculate the no of molecules and number of atoms present in 1.2g of ozone.​

Answer 1

Answer:

atoms-3/40 na

molecules-1/40na

Explanation:

Answer 2

Given: 1.2 grams of ozone.

To find: We have to find the number of molecules and number of atoms.

Solution:

The chemical formula of ozone is $O_3$.

The atomic weight of an oxygen atom is 16 grams.

Thus the molecular weight of ozone is 16×3=48 grams.

Now we can write-

48 grams of ozone contains $6.023×10^{23}$ number of molecules.

Thus 1.2 g of ozone contains $6.023×10^{23}×1.2/48=0.09×10^{23}$ number of molecules.

Thus 1.2 g of ozone contains $0.09×10^{23}$ number of molecules.

Again 48 grams of ozone contains $3×6.023×10^{23}=18.069×10^{23}$ number of oxygen atoms.

Thus 1.2 grams of ozone contains $18.069×10^{23}×1.2/48=0.27×10^{23}$ number of oxygen atoms.

Thus 1.2 grams of ozone contains $0.27×10^{23}$ number of oxygen atoms.