Calculate the no of molecules atom electron present in 8.5 g ammonia gas apso calculate its volume at stp
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One mole of any gas occupies about 22.4 litres of space at STP.
Also, I mole contains Avogadro's number of molecules.
So, one mole of NH3 occupies 22.4 litres and has 6.022 × 10^23 molecules.
Therefore 1 litre contains 1 ÷ 22.4 moles.
Thus:
10 litres contain 10 ÷ 22.4 moles.
Therefore :
10 litres contain about 0.446 moles of NH3.
Now for number of molecules:
1 mole of NH3 contains 6.022 × 10^23 molecules.
Thus 0.446 moles of NH3 contain 6.022 × 10^23 × 0.446 molecules
= 2.6851 × 10^23 molecules.
Multiply by 4 for number of atoms.
This gives final answer:
2.6851 × 4 × 10^23 ATOMS.
Thanks
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Is this answer still relevant and up to date?
Simple, apply PV=nRT
v is volume which is 10 litres in your case
Pressure and temperature are given because it is standard temperature and pressure
n is the number of moles of molecules of ammonia or any other gas.
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Please rottet the image
342 Views ·
At stp any element of one mole quantity consumes 22.4ltr.
Given the sample occupies 10ltrs do the direct ratio calculation to the number of moles.
After getting number of moles multiply it by avagadro number
280 Views ·
Unfortunately, one answer (by Adit Akarsh) seems to have used the wrong value for "Avogadro's number". The correct value is about 6.022 x 10^23.
Yash Chavan's answer seems correct, but it contains some approximations, as is usual with this sort of question.
2.2k Views · Answer requested by
1 mole of ammonia gas at STP = 22.4L therefore 1 ml ( 0.001L) of ammonia gas is 0.446428 x 10^-3 moles 1mole=6.022 × 10^23 molecules therefore 0.446428 * 10^-3 moles=0.2688 x 10^20 molecules of ammoni...
, Chemical engineer with a reasonable understanding of the natural sciences
Alec is right, powers of 10 get huge fast. Do you have a concept for how large 10^82 is? Probably not, it's not something intuitive, so let's give you some perspective: A golf ball has a diameter ...
Also, I mole contains Avogadro's number of molecules.
So, one mole of NH3 occupies 22.4 litres and has 6.022 × 10^23 molecules.
Therefore 1 litre contains 1 ÷ 22.4 moles.
Thus:
10 litres contain 10 ÷ 22.4 moles.
Therefore :
10 litres contain about 0.446 moles of NH3.
Now for number of molecules:
1 mole of NH3 contains 6.022 × 10^23 molecules.
Thus 0.446 moles of NH3 contain 6.022 × 10^23 × 0.446 molecules
= 2.6851 × 10^23 molecules.
Multiply by 4 for number of atoms.
This gives final answer:
2.6851 × 4 × 10^23 ATOMS.
Thanks
5.9k Views ·
Your feedback is private.
Is this answer still relevant and up to date?
Simple, apply PV=nRT
v is volume which is 10 litres in your case
Pressure and temperature are given because it is standard temperature and pressure
n is the number of moles of molecules of ammonia or any other gas.
3.8k Views ·
Please rottet the image
342 Views ·
At stp any element of one mole quantity consumes 22.4ltr.
Given the sample occupies 10ltrs do the direct ratio calculation to the number of moles.
After getting number of moles multiply it by avagadro number
280 Views ·
Unfortunately, one answer (by Adit Akarsh) seems to have used the wrong value for "Avogadro's number". The correct value is about 6.022 x 10^23.
Yash Chavan's answer seems correct, but it contains some approximations, as is usual with this sort of question.
2.2k Views · Answer requested by
1 mole of ammonia gas at STP = 22.4L therefore 1 ml ( 0.001L) of ammonia gas is 0.446428 x 10^-3 moles 1mole=6.022 × 10^23 molecules therefore 0.446428 * 10^-3 moles=0.2688 x 10^20 molecules of ammoni...
, Chemical engineer with a reasonable understanding of the natural sciences
Alec is right, powers of 10 get huge fast. Do you have a concept for how large 10^82 is? Probably not, it's not something intuitive, so let's give you some perspective: A golf ball has a diameter ...
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