Calculate the no.of molecules if so2 present in 44g of it
Answers
Answered by
8
Molar mass of SO₂ is 64 g
64 g Sulphur dioxide contains 6.022 × 10²³ molecules
n = (44 g / 64 g) × 6.022 × 10²³ molecules
= 4.14 × 10²³ molecules
∴ There are 4.14 × 10²³ molecules in 44 g of Sulphur dioxide
64 g Sulphur dioxide contains 6.022 × 10²³ molecules
n = (44 g / 64 g) × 6.022 × 10²³ molecules
= 4.14 × 10²³ molecules
∴ There are 4.14 × 10²³ molecules in 44 g of Sulphur dioxide
Similar questions