Question

Calculate the no.of molecules in 8g of oxygen gas and 28g of nitrogen gas.(mol. Wt. O=32, n=14)​

Answer 1

Answer:

No. of molecules in 8g of oxygen gas is 0.26 moles

No.of molecules in 28g of nitrogen gas is 2 moles

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Explanation:

No of molecules=

$\frac{molar mass}{molecular \: weight}$

Answer 2

Explanation:

To Find -

• No. of molecules in 8 g of O2 and 28 g of N2

Solution -

1)

8 g of O2

GAM = 16 × 2 = 32 g/mol

mole = 8/32

mole = 1/4

Number of molecules = mole × 6 × 10²³

→ 1/4 × 6 × 10²³ [6.022 × 10²³ ≈ 6 × 10²³]

→ 1.5 × 10²³

Hence,

1.5 × 10²³ molecules are present in 8 g of O2.

2)

28 g of N2

GAM = 14 × 2 = 28 g/mol

mole = 28/28

mole = 1

Number of molecules = mole × 6 × 10²³

→ 1 × 6 × 10²³

→ 6 × 10²³

Hence,

6 × 10²³ molecules present in 28 g of N2.