Question

calculate the no. of molecules of sulphur present in 16g of solid sulphur​

Answer 1

$\purple{\huge{\bold{\mathcal{Answer}}}}$

formula

$\large{moles=given\:mass/molar\:mass}$

Given mass of solid sulphur ➡16g

molar mass of sulphur➡32u

Then the no. of moles is

$moles = \frac{16g}{32u}$

$\orange{\huge{\bold{\boxed{\mathcal{0.5moles}}}}}$

1mol=6.022 x 10^23 molecules

Then

0.5mol=0.5 x 6.022 x 10^23

= 3.011 x 10^23 molecules

Answer 2

Explanation:

no of moles = mass given / gram molecular mass

= 16/32 = 2

if 1 mole = 6.022 × 10^23 molecules

then 2 moles of solid sulphur = 6.022 × 10^23 × 2

= 1.2044 × 10^24 molecules

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