calculate the no. of molecules on 50 g of CaCo3
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Explanation:
No. of molecules in 100g of CaCO3 = 6.022× 10^23
No. of molecules in 1g = 6.022× 10^23/100
No. of molecules in 50g = 6.022× 10^23/100 × 50
= 6.022 × 10^23/2
= 3.011 × 10^23 molecules
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