Calculate the no. of molecules present in 16.8l of gas 'X' at stp
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4.5165×10²³ molecules
Explanation:-
We know that, volume of one mole of any gas at STP is 22.4L
Also at STP, number of moles of the gas 'X' is 1.
• 1 mole = 6.022 × 10²³ molecules
Hence, 6.022×10²³ molecules are present in 22.4 L of the gas 'X'.
∴ Number of molecules present in 16.8L :-
= 16.8×6.022×10²³/22.4
= 101.1696×10²³/22.4
= 4.5165×10²³ molecules
Thus, 4.5165×10²³ molecules are present in 16.8 L of the gas 'X' at STP.
Some Extra Information:-
At STP 'Standard Temperature and Pressure', a system [only gases] are said to have :-
• Temperature = 0° C
• Pressure = 1 atm
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