Calculate the no. Of moles and find out no. Of molecules (i.)12g of ozone gas
ii.)20g of H^2O^2
iii.)22g of sulphur oxide
Answers
Explanation:
1. In a reaction 5.3 g of sodium carbonate reacted with 6 g of ethanoic acid. The products were 2.2 g of carbon dioxide, 0.9 g water and 8.2 g of sodium ethanoate. Show that these observations are in agreement with the law of conservation of mass carbonate.
Ans.
Sodium carbonate+Ethanoic acid→Sodium ethanoate+Carbon dioxide+Water5.3 g+6 g→8.2 g+2.2 g+0.9 g
LHS RHS
11.3 g = 11.3 g
(Mass of reactant) (Mass of product)
This shows, that during a chemical reaction mass of reactact = mass of product.
2. Hydrogen and oxygen combine in the ratio of 1 : 8 by mass to form water. What mass of oxygen gas would be required to react completely with 3 g of hydrogen gas?
Ans. Ratio of H : O by mass in water is:
Hydrogen : Oxygen → H2O
1 : 8 = 3 : x
x = 8 × 3
∴ 24 g of oxygen gas would be required to react completely with 3 g of hydrogen gas...