Question

calculate the no. of moles and molecules of ammonia present in 5.6 dm^3 of its volume

Answer 1

Hi mate.

Thanks for asking this question.

Here is your answer,


Given :

V = 5.6 dm3 = 5.6L

Then ,

We know that,

n = V / 22.4 L

n = 5.6 / 22.4

n = 56 / 224

n = 1 / 4

n = 0.25 mole.


And for the no of molecules,

We have a concept,

No. Of molecules = n × avagdro number


$no \: of \: molecule \: = 0.25 \times 6.022 \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \times {10}^{23}$
$no \: of \: molecules \: = 1.5 \times {10}^{23}$




Thank you.




BE BRAINLY !!!!!!!

Answer 2

……I HOPE YOU UNDERSTAND…………^_^