Question

Calculate the no.Of moles and no.Of molecules present in 1.4g of ethylene gas. What is the volume occupied by the same amount of c2h4. State the vapour density of c2h4

Answer 1

Answer:

Explanation:

(a) Mass of ethylene gas = 1.4 g Number of molecules is 0.05 mole ethylene = C2H2 = mass/molar mass = 1.4/28 = 0.5 Number of molecules in 0.05 mole ethylene = 0.05 x 6 x 1023 = 3 x 1022 molecules 1 mole of ethylene has volume at s.t.p. = 22.4 lit. Volume occupied by 0.05 moles of ethylene gas at s.t.p. = 0.05 x 22.4 = 112 lit. (b) Vapour density of ethylene = mol.wt/2 = 28/2 = 14