calculate the no of moles If the given mass of mg2 is 36 g
Answers
Answered by
0
Answer:
2Mg+O
2
→2MgO
1 mole of O
2
is required for 2 Moles of Mg
5 Moles of O
2
is required for 10 Moles of Mg
So , 32×5g of O
2
is required = 160 g
160 g of O
2
is required to combust 10 Moles of Mg
:hope this will help you
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Answered by
0
Answer:
Number of moles(n) = Given weight(W)/Molecular Mass(M)
n = W/M
n= 36/48
n= 0.75moles
Hope it helps you!
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