Question

calculate the no.of moles in 0.008g of phosphorus

Answer 1

Hi mate.

Thanks for asking this question.

Here is your answer,


Given :

W = 0.008g.

M = P

= 30.

We know that,


For calculating the no. of moles.




$n = \frac{w}{m}$


$n \: = \: \frac{8 \times {10}^{ - 3} }{30}$

$n \: = \frac{4 \times {10}^{ - 3} }{15}$

$n \: = \: 0.266 \times {10}^{ - 3}$


$n \: = \: 2.6 \times {10}^{ - 4}$


Thank you.



BE BRAINLY !!!!!!!!

Answer 2

Try using the formula

n=mass given/molecular mass