calculate the no of moles in 3.011*10^17 molecules of caco3
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Answered by
11
Answer:
No. of moles=?
No. of molecules=3.011×10∧17
Ionic mass of CaCO3= 40+12+48=100g/mol
Explanation:
No. of molecules= No. of moles×6.02 ×10∧23
No. of moles= No. of molecules/ 6.02 ×10∧23
=(3.011×10∧17)÷(6.02×10∧23)
No. of moles =5.0016×10∧-7
Answered by
6
According to avogadro's law, 1 mole of every substance weighs equal to the molecular mass and contains avogadro's number 6.023×10^23 of particles.
Given :
Number of atoms of carbon = 3.011×10^23
Thus 6.023×10^23 atoms of carbon = 1 mole
3.011 ×10^23 atoms of carbon=
(1/(6.023×10^23))×3.011×10^23=0.5 moles
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