Question

calculate the no.of moles in 31.5 of HNo3 ​

Answer 1

Answer:

$\begin{array}{|c|c|c|c|c|c|c|c|c|} \hline X & \: 14 & 15 & 16 & 17 & 18 & 19 & 20 & 21 \\ \\ \hline P(X) & \frac{2}{15} & \frac{1}{15} & \frac{2}{15} & \frac{3}{15} & \frac{1}{15} & \frac{2}{15} & \frac{3}{15} & \frac{1}{15} \\ \\ \hline \end{array}$

Answer 2

No. of moles in 31.5g of HNO$_{3}$ is 0.5 mole

Explanation:

Atomic mass

• H - Hydrogen = 1

• N - Nitrogen   = 14

• O - Oxygen    = 16

One mole of HNO$_{3}$ = H + N + (O*3)

                                = 1 + 14+ (16*3)

                                = 63g/mol

for, 31.5g of HNO$_{3}$ = $\frac{given no. of mole of HNO_{3} } {1^{} mole^{} of HNO_{3} }$

                                = $\frac{31.5}{63}$

                               = 0.5 mol