calculate the no. of moles in 36g of water (H²O).(H=1u,O=16u)
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If we have one mole of water, then we know that it will have a mass of 2 grams (for 2 moles of H atoms) + 16 grams (for one mole O atom) = 18 grams. Since we only have 0.001 grams, that means that we have NA * (0.001/18) = 3.35*1019 molecules of water.
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Answer:
no.of moles =mass of water/molecular mass of water
molecular mass of water=H2O=(1)2+16=2+16=18
no.of moles =36/18=2
therefore two moles of water are present in 36g of water
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