Question

calculate the no. of moles in the following:
1. 10 grams of carbon Tetrachloride.
2. 5 grams of ozone gas
3. 0.2 grams of aluminum sulphate.​

Answer 1

Answer:

no. of moles = mass given / molar mass

1 :-

10 g CCl⁴

molar mass = 152 g

$= \frac{10}{152} \\ = 0.06 \: mole$

2:-

5 g O³

molar mass = 48

$= \frac{5}{48} \\ = 0.10 \: mole$

3:- 0.2 g of Al²(SO³)²

molar mass = 342 g

$= \frac{0.2}{342} \\ = 0.00058 \: moles$