Question

Calculate the no. of moles in the following masses :
1) 1.46 metric tons of Al
2) 7.9 mg of Ca​

Answer 1

Answer:

it is 1.46m tons and 7.9mgand thanks thoko friends plzz

Answer 2

Q. Calculate the no. of moles in the following masses :

Calculate the no. of moles in the following masses :1) 1.46 metric tons of Al

Calculate the no. of moles in the following masses :1) 1.46 metric tons of Al2) 7.9 mg of Ca

$ans = moles \: of \: almunium = 5.41 \times {10}^{4}$

$moles \: of \: calcium = 1.97 \times {10}^{ - 4}$

Explanation:-

$1.6 \: metric \: tones \: of \: al \: = 1.46 \times {10}^{3} \times {10}^{3} g \: of \: almunium$

$= 1.46 \times {10}^{6} g$

$atomic \: mass \: of \: almunium \: = 27$

$moles \: of \: almunium \: = \frac{mass \: of \: almunium}{atomic \: mass}$

$= \frac{1.46 \times {10}^{6} }{27}$

$= 5.41 \times {10}^{4} mol$

$7.9 \: mg \: of \: calcium \: = 7.9 \times {10}^{ - 3} g \: of \: ca$

$atomic \: mass \: of \: calcium = 40.1$

$moles \: of \: ca \: = \frac{ mass \: of \: ca}{atomic \: mass}$

$= \frac{7.9 \times {10}^{ - 3} }{40.1}$

$= 1.97 \times {10}^{ - 4} mol$