Calculate the no. Of moles, molecules and total no.of atom present in 0.32 mg of methane
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methane Ch4
molecular mass 16 g
16 g........ > I mole :0.32 g.......... > o. o2 moles
16g......... > 6.022 X 10²³ molecules. :0.32 gives 1.2 X 10²² molecules
no of atoms will be 5 X 1.2 X 10²²=6.0. x10²² atoms
methane Ch4
molecular mass 16 g
16 g........ > I mole :0.32 g.......... > o. o2 moles
16g......... > 6.022 X 10²³ molecules. :0.32 gives 1.2 X 10²² molecules
no of atoms will be 5 X 1.2 X 10²²=6.0. x10²² atoms
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