Question

calculate the no of moles of 800g NaOH dissloved in 1000 ml solution​

Answer 1

SolutioN :-

$\longrightarrow\boxed{ \bf Mole = \frac{Given \: mass} {Molecular \: mass}}$

Here

• Given mass = 800 g

• Molecular mass of NaOH = 23 + 16 + 1 = 40 mol/g

$\longrightarrow\sf Mole = \frac{800}{40} \\ \\\longrightarrow \sf Mole = 20 \: mol$

Answer 2

Answer:

The answer is there in the attachment