calculate the no. of moles of 9 gm of
h2o
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Answer:
Water(H2O) has a molecuar mass of 18, this means it weights 18 g per mole. A mole is 6.0221415*1023molecules (Avogadro's number). If you have 1 g of water, you therefore have 1/18 of a mole, or 3.34*1022 molecules.
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Explanation:
no of moles of water = 9 g / 18 g =1/2 moles
so no of molecules present = no of moles × N(A)
=1/2 × 6.022×10^23
= 3.011×10^23
no of moles = 17/17= 1 mole
no of molecules = 1 × 6.022× 10^23
=6.022×10^23
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