Calculate the no. of moles of elections
in 0.55mg of electrons?
Molar volume 9-1810 31x6.022x10²3
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Answer:
Mass of electron e = 9.1×10^-31 kg
Number Of electrons in 0.55 mg=0.55/9.1×10^-31=0.604×10^30
Number of moles = number of electrons/Avogadro's number
Number of moles = 0.604×10^30/6.023×10^23= 1003479.3 moles per kg
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