Calculate the no. Of moles of ethylene required to produce 44g of carbon dioxide on its complete combustion
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Mass of glucose is 180g
Mass of CO2 formed in reaction is 44 x 6 is equal to264g
So glucose required is 180 x 44 divided by 264 gives 30 g
Answer is 30g
Mass of CO2 formed in reaction is 44 x 6 is equal to264g
So glucose required is 180 x 44 divided by 264 gives 30 g
Answer is 30g
Answered by
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glucose required is 180 x 44 divided by 264 gives 30 g
Answer is 30g
Answer is 30g
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