Question

calculate the no. of moles of MnO4- reduced to mn2+ by the addition of 7.5 mole electrons in MnO4-

Answer 1

Please mark me brainliest and follow me

5 moles of electrons must be added to MnO₄⁻ to get reduced to Mn²⁺

So, 7.5 moles of electrons will reduce:

$\frac{7.5}{5}$ = 1.5 moles of MnO₄⁻ will get reduced in 7.5 moles of electrons to produce 1.5 moles of Mn²⁺

Answer 2

Given:

The no of moles of electrons = 7.5

To Find:

The no. of moles of MnO₄⁻ reduced to Mn²⁺ by the addition of 7.5 moles of electrons.

Calculation:

- The balanced equation for the reduction of MnO₄⁻ to Mn²⁺ is:

MnO₄⁻ + 8 H⁺ + 5 e⁻ → Mn²⁺ + 4 H₂O

⇒ The no of moles of MnO₄⁻ reduced by 5 moles of electrons = 1

⇒ The no of moles of MnO₄⁻ reduced by 7.5 moles of electrons = (1/5) × 7.5

⇒ The no of moles of MnO₄⁻ reduced = 1.5

- So, 7.5 moles of electrons will reduce 1.5 moles of MnO₄⁻ to Mn²⁺.