Question

calculate the no of moles of nitrogen in 4.0 x 10^ -3 kg amonium nitrate​

Answer 1

Explanation:

Check it again, I think that your soil is too heavy. It mean that volume weight of your soil is around 5 kilo per liter ?

volume of truncated cone is: V=1/3 x Pi x h x (R2+Rr+r2)

V = 1/3 x 3,14 x 9 cm (4,52 + 4,5+3,5 + 3,52) = 1/3 x 28,26 x 48,25 = 1365/3 = 455 cm3 = 0,455 dm3 of soil (if pot is fulfilled)

I think that you have to reserve 55 cm3 for watering, so your pot have 0,4 dm3 of soil

For 0,4 dm3 of soil you need 58,5 mg of NH4NO3 per each pot.

Answer 2

Explanation:

Since the orbitals must fill in order, this tells you number of orbitals that must already be full. For example, an atom with the quantum numbers 4,1,0 has a principal quantum number of 4. This means that 3 orbitals are already full. Add the maximum number of electrons that each full orbital can hold

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