Question

Calculate the no.of moles of phosphorus in 92.2 g of P assuming that molecular formula of P is P4​

Answer 1

Answer:

given mass of phosphorous = 92.9g

molar mass of phosphorous (P4) = 123.88g mol-1

no. of mole of phosphorous = 92.9 ÷ 123.88 = 0.75 mol

no. of molecules present = 0.75 × 6.023 × 10power26 = 4.52 × 10power26

no. of atoms present = (92.9 ÷ 30.97) × 6.023 × 10power26 = 3 × 6.023 × 10power26 = 18.069×10power26

Answer 2

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