Question

Calculate the no of moles present in12.044 x1023

particles of Sulphur.​

Answer 1

Answer:

Explanation:

One mole of any element contains 6.022 X 1023 atoms of the element. Thus 1 mole of He atom consists of 6.022 X 1023 atoms of He. Thus

6.022 X 1023 atoms of He = 1 mole of He atom

1 atom of He = 1 / ( 6.022 X 1023) moles of He

So 12.044 X 1023 atoms of He = ( 1 X 12.044 X 1023) / ( 6.022 X 1023) moles of He

= 2 moles of He atom

Thus there are 2 moles of He atom in 12.044 X 1023 atoms of He.

Answer 2

Answer

For Helium,

Number of atoms=Number of moles ×6.022×10  

23

 

No of Moles =  

6.022×10  

23

 

12.044×10  

23

 

​  

 = 2.

Now, atomic mass of He=4

Weight = 2×4 = 8 g