Question

calculate the no
of neutron in
1.8gm of glucose​

Answer 1

Answer:

How many neutrons are present in one gram of glucose?

Formula of glucose is C6H12O6. Its molecular mass is (6×12)+(12×1)+(6×16)=180.Assuming that all the atoms of Carbon are of the isotope C-12, Hydrogen-1 and oxygen-16, we know that each- carbon atom has 6 neutrons,hydrogen 0 and oxygen has 8 neutrons in their nucleus.

Hence in 1 molecule of glucose there are (6×6)+(6×8) neutrons i.e. 84 neutrons.

180 g ( i.e. 1mole) of glucose has 6. 022× 10^23 molecules

Hence in 1g of glucose there are (6.022× 10^23) / 180 molecules

1 molecule has = 84 neutrons

(6.022×10^23)/180 molecules have= 84×(6.022×10^23)/ 180= 2.81×10^23 neutrons

Explanation:

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