calculate the no. of of molecule in 1cm3 of an ideal gas NTP
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1 mol of any gas at NTP occupies volume of 22400 cm³
Volume of 6.022 × 10²³ molecules of gas = 22400 cm³
Number of molecules in 1 cm³ of Volume
= 1 cm³ × 6.022 × 10²³ molecules / (22400 cm³)
= 2.7 × 10¹⁹ molecules
Volume of 6.022 × 10²³ molecules of gas = 22400 cm³
Number of molecules in 1 cm³ of Volume
= 1 cm³ × 6.022 × 10²³ molecules / (22400 cm³)
= 2.7 × 10¹⁹ molecules
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